5. In Fig. 6.43, if PQ PS, PQ SR, SQR = 28° and QRT = 65°, then find the values of x and y.
PQ PS, PQ || SR, SQR = 28° and QRT = 65°
Now, In QRS, the side SR produced to T and PQ || RS
therefore, QRT = =
Also, QRT = RSQ + SQR (By exterior angle property of a triangle)
Therefore, RSQ = QRT - SQR
Now, in PQS,
P + PQS + PSQ =