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3.  In Fig., \small \angle B <\angle A  and \small \angle C <\angle D. Show that \small AD <BC.


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In this question, we will use the property that sides opposite to larger angle are larger.

We are given \small \angle B <\angle A  and \small \angle C <\angle D . 

Thus,                     BO\ > AO              ..............(i)

and                        OC\ > OD             ...............(ii)

Adding (i) and (ii), we get :

                          AO\ +\ OD\ <\ BO\ +\ OC

or                                        AD\ <\ BC 

Hence proved.

Posted by

Devendra Khairwa

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