Q : 11 In Fig. , ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that
We have a pentagon ABCDE in which BF || AC and CD is produced to F.
(i) Since ACB and ACF are on the same base AC and between same parallels AC and FB.
ar(ACB) = ar (ACF)..................(i)
(ii) Adding the ar (AEDC) on both sides in equation (i), we get
ar(ACB) + ar(AEDC) = ar (ACF) + ar(AEDC)