Q: 5 In Fig. , ABC and BDE are two equilateral triangles such that D is the mid-point of BC. If AE intersects BC at F, show that
[Hint: Join EC and AD. Show that and , etc.]
Since ABC and BDE are equilateral triangles.
Therefore, ACB = DBE =
BE || AC
BAE and BEC are on the same base BE and between same parallels BE and AC.
Therefore, ar (BAE) = ar(BEC)
ar(BAE) = 2 ar(BED) [since D is the meian of BEC ]