# Q : 5        In Fig., ABC and BDE are two equilateral triangles such that D is the mid-point of BC. If AE intersects BC at F, show that (v) [Hint : Join EC and AD. Show that   and  , etc.]

In right angled triangle ABD, we get

So, in PED,

So,

Therefore, the Area of ..........(i)

And, Area of triangle ...........(ii)

From eq (i) and eq (ii), we get
ar(AFD) = 2. ar(EFD)
Since ar(AFD) = ar(BEF)

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