Q : 8 In Fig. , ABC is a right triangle right angled at A. BCED, ACFG and ABMN are squares on the sides BC, CA and AB respectively. Line segment meets BC at Y. Show that:
Since ||gm CYXE and ACE lie on the same base CE and between the same parallels CE and AX.
Therefore, 2. ar(ACE) = ar (||gm CYXE)
But, FCB ACE (in iv part)
Since the congruent triangle has equal areas. So,