Q: 4 In Fig. , P is a point in the interior of a parallelogram ABCD. Show that
[Hint : Through P, draw a line parallel to AB.]
We have a ||gm ABCD and AB || CD, AD || BC. Through P, draw a line parallel to AB
Now, APD and ||gm ADGHare on the same base AD and between the same parallels GH and AD.
Therefore, ar (APD) = 1/2 . ar(||gm ADGH).............(i)
Similarily, ar (PBC) = 1/2 . ar(||gm BCGH)............(ii)
By adding the equation i and eq (ii), we get