Q: 5 In Fig.9.33, ABC and BDE are two equilateral triangles such that D is the mid-point of BC. If AE intersects BC at F, show that
[Hint: Join EC and AD. Show that and , etc.]
Since ABC and BDE are equilateral triangles.
Therefore, ACB = DBE =
BE || AC
BDE and AED are on the same base ED and between same parallels AB and DE.
Therefore, ar(BED) = ar(AED)
On subtracting EFD from both sides we get
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