# Q. 10.     In the following figure, find the area of the shaded portion:

R

Area  of shaded portion = Area of the whole rectangle ( ABCD ) - Area of two triangles ( AFE and BCE)

Area of the rectangle with length 18 cm and width 10 cm is

$\Rightarrow length \times breadth = 18 \times 10 = 180 \ cm^2$

Area of triangle AFE with base 10 cm and height 6 cm is

$\Rightarrow \frac{1}{2} \times \ base \times height =\frac{1}{2} \times 10 \times 6 = 30 \ cm^2$

Area of triangle BCE with base 8 cm and height 10 cm is

$\Rightarrow \frac{1}{2} \times \ base \times height =\frac{1}{2} \times 8 \times 10 = 40 \ cm^2$

Now, Area  of the shaded portion is

$\Rightarrow 180 - (40+30)$

$\Rightarrow 180 - 70 = 110 \ cm^2$

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