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Q19  Integrate the functions e ^ x \left ( \frac{1 }{x} - \frac{1}{x^2}\right )

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e ^ x \left ( \frac{1 }{x} - \frac{1}{x^2}\right )
It is known that
\int e^x[f(x)+f'(x)]=e^x[f(x)]+C

let 
f(x)=\frac{1}{x}\Rightarrow f'(x)=-\frac{1}{x^2}
Therefore the required solution of the given above integral is 
I = e^x.\frac{1}{x}+C

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manish

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