Q

# Is the function defined by f (x) = x ^ 2 - sin x + 5 continuous at x = p?

20. Is the function defined by $f (x) = x^2 - sin x + 5$ continuous at x = $\pi$?

Views

Given function is
$f (x) = x^2 - sin x + 5$
Clearly, Given function is defined at x =$\pi$
$f(\pi) = \pi^2-\sin \pi+5 =\pi^2-0+5 = \pi^2+5\\ \lim_{x\rightarrow \pi}f(x) = \pi^2-\sin \pi+5 =\pi^2-0+5 = \pi^2+5\\ \lim_{x\rightarrow \pi}f(x) = f(\pi)$
Hence, the function defined by $f (x) = x^2 - sin x + 5$ continuous at x = $\pi$

Exams
Articles
Questions