Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

Q. 18 Let $f : R \rightarrow R$ be the Signum Function defined as

$f(x) = \left\{\begin{matrix} 1 & x> 0 \\ 0 &x = 0 \\ -1& x < 0 \end{matrix}\right.$

and $g : R \rightarrow R$ be the Greatest Integer Function given by $g (x) = [x]$ , where $[x]$ is greatest integer less than or equal to $x$ . Then, does $fog$ and $gof$ coincide in $(0, 1]$ ?

Answers (1)

best_answer

$f : R \rightarrow R$ is defined as $f(x) = \left\{\begin{matrix} 1 & x> 0 \\ 0 &x = 0 \\ -1& x < 0 \end{matrix}\right.$

$g : R \rightarrow R$ is defined as $g (x) = [x]$

Let $x \in (0, 1]$

Then we have , $[1]=1$ if x=1 and $[x]=0\, \, \, \, \, if\, 0< x< 1$

$\therefore \, \, \, \, fog(x)=f(g(x))=f(\left [ x \right ]) = \left\{\begin{matrix}f(1) & x= 0 \ \\ f(0)& x \in (0,1) \end{matrix}\right = \left\{\begin{matrix}1 & x= 0 \ \\ 0& x \in (0,1) \end{matrix}\right$

$\therefore \, \, gof(x)=g(f(x))=g(1)=\left [ 1 \right ]=1\, \, \, \,(since \, \, x> 0)$

Hence,for $x \in (0, 1]$ , $fog(x)=0$ and $gof(x)=1$ .

Hence , gof and fog do not coincide with $(0, 1]$ .

Posted by

seema garhwal

View full answer

Crack CUET with india's "Best Teachers"

HD Video Lectures
Unlimited Mock Tests
Faculty Support

cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Single Girl Child Scholarship 2024: Registration extended till January 10; eligibility criteria, amount

anam-khan

CBSE wants international boards reined in; letter to education ministry seeks directions for AIU

anam-khan

PM Modi's Pariksha Pe Charcha 2025 to be held next month, registrations open till January 14

Latest Question