# 5.  Line $\small l$ is the bisector of an angle $\small \angle A$ and $\small B$  is any point on $\small l$. $\small BP$ and $\small BQ$ are perpendiculars from $\small B$ to the arms of $\small \angle A$ (see Fig. ). Show that:            (ii) $\small BP=BQ$ or $\small B$ is equidistant from the arms of  $\small \angle A$.

In the previous part we have proved that    $\small \Delta APB\cong \Delta AQB$.

Thus by c.p.c.t. we can write :

$BP\ =\ BQ$

Thus B is equidistant from arms of angle A.

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