8.32 Name the members of the lanthanoid series which exhibit +4 oxidation states and those which exhibit +2 oxidation states. Try to correlate this type of behaviour with the electronic configurations of these elements.

Answers (1)

Members of the lanthanoids which exhibits +4 oxidation states are- Ce, Pr,Nd,Tb,Dy
members who exhibit +2 oxidation states = Nd,Sm,Eu,Tm,Yb

After losing 4 electrons Ce^{4+}attains stable configuration [Xe] and also the same thing happen to Tb = [Xe]4f^{7}

In the case of Eu and Yb ,  after losing two electrons they also get their stable electronic configuration.
\\Eu^{2+}=[Xe]4f^{7}\\ Yb^{2+}= [Xe]4f^{14} 

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