# 2. One of the angles of a triangle is $\small 80^{\circ}$ and the other two angles are equal. Find the measure of each of the equal angles.

P Pankaj Sanodiya

Let the two same angles in triangle be $x$.

Now,  As we know the sum of internal angles of a triangle is 180. so,

$80^0+x+x=180^0$

$2x=180^0-80^0$

$2x=100^0$

$x=50^0$.

Hence both other angles are $50^0$ each.

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