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One of the angles of a triangle is 80 degrees and the other two angles are equal. Find the measure of each of the equal angles.

2. One of the angles of a triangle is \small 80^{\circ} and the other two angles are equal. Find the measure of each of the equal angles.

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Let the two same angles in triangle be x.

Now,  As we know the sum of internal angles of a triangle is 180. so,

80^0+x+x=180^0

2x=180^0-80^0

2x=100^0

x=50^0.

Hence both other angles are 50^0 each.

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