2.   Organise the following marks in a class assessment, in a tabular form.
  4, 6, 7, 5, 3, 5, 4, 5, 2, 6, 2, 5, 1, 9, 6, 5, 8, 4, 6, 7
(i) Which number is the highest? (ii) Which number is the lowest?
(iii) What is the range of the data? (iv) Find the arithmetic mean.

Answers (1)
H Harsh Kankaria
Numbers Frequency
1 1
2 2
3 1
4 3
5 5
6 4
7 2
8 1
9 1

(i) 9 is the highest number.

(ii) 1 is the lowest number

(iii) Range of the data = Highest number - Lowest number

9-1=8

(iv) Arithmetic mean = \frac{sum\ of\ observations}{number\ of\ observation}

= \frac{(1\times1) + (2\times2) + (3\times1)+ (4\times3 )+ (5\times5 )+ (6\times4) + (7\times2)+(8\times1)+(9\times1)}{20}

\\ = \frac{1 +4 +3 +12+ 25+ 24 +14 +8 +9}{20} \\\\ = \frac{100}{20} \\\\ = 5

Therefore, mean of the data is 5

 

 

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