# 2.   Organise the following marks in a class assessment, in a tabular form.   4, 6, 7, 5, 3, 5, 4, 5, 2, 6, 2, 5, 1, 9, 6, 5, 8, 4, 6, 7 (i) Which number is the highest? (ii) Which number is the lowest? (iii) What is the range of the data? (iv) Find the arithmetic mean.

H Harsh Kankaria
 Numbers Frequency 1 1 2 2 3 1 4 3 5 5 6 4 7 2 8 1 9 1

(i) $9$ is the highest number.

(ii) $1$ is the lowest number

(iii) Range of the data = Highest number - Lowest number

$9-1=8$

(iv) Arithmetic mean = $\frac{sum\ of\ observations}{number\ of\ observation}$

$= \frac{(1\times1) + (2\times2) + (3\times1)+ (4\times3 )+ (5\times5 )+ (6\times4) + (7\times2)+(8\times1)+(9\times1)}{20}$

$\\ = \frac{1 +4 +3 +12+ 25+ 24 +14 +8 +9}{20} \\\\ = \frac{100}{20} \\\\ = 5$

Therefore, mean of the data is $5$

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