Q : 8  Parveen wanted to make a temporary shelter for her car, by making a box-like structure with tarpaulin that covers all the four sides and the top of the car (with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make the shelter of height \small 2.5\hspace {1mm}m, with base dimensions \small 4\hspace {1mm}m\times 3\hspace {1mm}m?

Answers (1)

Given, Dimensions of the tarpaulin = 4\ m\times 3\ m \times2.5\ m

The required amount of tarpaulin = Lateral surface area of the shelter + Area of top

2(lh + bh )+ lbRequired

\\ = 2(4\times2.5 + 3\times2.5 )+ 4\times3 \\ = 2(10+7.5) + 12 = 47\ m^2

Therefore, 47\ m^2 tarpaulin is required. 

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