1.  PQR is a triangle, right-angled at P. If  \small PQ = 10\hspace{1mm}cm  and  \small PR = 24\hspace{1mm}cm, find QR.
 

Answers (1)

As we know, 

In a Right-angled Triangle: By Pythagoras Theorem,

(Hypotenus)^2=(Base)^2+(Perpendicular)^2

As PQR is a right-angled triangle with 

Base = PQ = 10 cm.

Perpendicular = PR = 24 cm.

Hypotenuse = QR

So, By Pythagoras theorem,

(QR)^2=(PQ)^2+(PR)^2

(QR)^2=(10)^2+(24)^2

(QR)^2=100+576

(QR)^2=676

QR=26 cm

Hence, Length od QR is 26 cm.

 

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