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# Predict the number of unpaired electrons in the square planar [Pt(CN)_{4}]^{2-}ion.

9.9     Predict the number of unpaired electrons in the square planar $[Pt(CN)_{4}]^{2-}$ion.

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The oxidation state of Pt in the given compound is +2. Also, it is given that the compound has square planar geometry i.e., it has dsp2 hybridisation (d8).

CN is a strong ligand so the pairing of electron will occur.

So there are be no unpaired electrons in the given compound.

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