8.18 Predict which of the following, will be coloured in aqueous solution?

Ti^{3+}, \:V^{3+}\:,\:Cu^+,\:Sc^{3+},\:Mn^{3+},\:Fe^{3+}\: and \:Co^{2+}

 

Answers (1)

Ions which have incomplete d-orbital, they are able to do d-d transition, which is responsible for colour. And those which has vacant d-orbitals or complete d-orbitals are colourless

Ti^{3+}=[Ar]3d^{1} Purple
V^{3+}=[Ar]3d^{1} green
Sc^{3+}=[Ar]3d^{0} colourless
Mn^{2+}=[Ar]^{18}d^{5}4s^{0} pink
Fe^{3+}   =[Ar]^{18}3d^{5}4s^{0} yellow
Co^{2+}=[Ar]^{18}d^{7}4s^{0} blue pink
Cu^{+} =[Ar]^{18}3d^{10}4s^{0} colourless

From the table, we notice that Sc^{3+} and Cu^{+} have 3d^{0} and 3d^{10} configuration, so their aqueous solutions are colourless. All others are coloured in aqueous medium.

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