Q: 5 Prove that the circle drawn with any side of a rhombus as diameter, passes through the point of intersection of its diagonals.
Given : ABCD is rhombus.
To prove : the circle drawn with AB as diameter, passes through the point O.
Proof :
ABCD is rhombus.
Thus, (diagonals of a rhombus bisect each other at )
So, a circle drawn AB as diameter will pass through point O.
Thus, the circle is drawn with any side of a rhombus as diameter passes through the point of intersection of its diagonals.