# Q: 5     Prove that the circle drawn with any side of a rhombus as diameter, passes through the point of intersection of its diagonals.

Given : ABCD is rhombus.

To prove : the circle drawn with AB  as diameter, passes through the  point O.

Proof :

ABCD is rhombus.

Thus, $\angle AOC = 90 \degree$             (diagonals of a rhombus bisect each other at $90 \degree$)

So, a circle drawn AB as diameter will pass through point O.

Thus,  the circle is drawn with any side of a rhombus as diameter passes through the point of intersection of its diagonals.

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