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Rationalise the denominators of the following: (ii) 1 upon square root 7 minus square root 6

5. Rationalise the denominators of the following:

    (ii)     \frac{1}{\sqrt{7}-\sqrt{6}}

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Given number is  \frac{1}{\sqrt{7}-\sqrt{6}}

Now, on rationalisation, we will get 

\Rightarrow \frac{1}{\sqrt 7-\sqrt6} = \frac{1}{\sqrt 7-\sqrt 6}\times \frac{\sqrt 7+\sqrt 6 }{\sqrt 7+\sqrt 6 } = \frac{\sqrt7+\sqrt 6}{(\sqrt7)^2-(\sqrt6)^2} = \frac{\sqrt7+\sqrt6}{7-6} = \sqrt7+\sqrt6
                                                                                                                          

Therefore, the answer is  \sqrt7+\sqrt6

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