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Rationalise the denominators of the following: (iv) 1 upon square root - 2

Q 5.     Rationalise the denominators of the following:

    (iv)     \frac{1}{\sqrt{7}-2}

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Given number is  \frac{1}{\sqrt{7}-2}

Now, on rationalisation we will get 

\Rightarrow \frac{1}{\sqrt 7-2} = \frac{1}{\sqrt 7- 2}\times \frac{\sqrt 7+ 2 }{\sqrt 7+ 2 } = \frac{\sqrt7+ 2}{(\sqrt7)^2-(2)^2} = \frac{\sqrt7+2}{7-4}
                                                                                                        = \frac{\sqrt7+2}{3}

Therefore, answer is  \frac{\sqrt7+2}{3}

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