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# Show that the general solution of the differential equation is given by (x + y + 1) = A (1 - x - y - 2xy), where A is parameter.

Q7.    Show that the general solution of the differential equation $\frac{dy}{dx} + \frac{y^2 + y + 1}{x^2 + x + 1} = 0$ is given by $(x + y + 1) = A (1 - x - y - 2xy)$, where A is parameter.

Views

Given,

$\frac{dy}{dx} + \frac{y^2 + y + 1}{x^2 + x + 1} = 0$

Integrating both sides,

Let

Let  A =

Hence proved.

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