# 2.  Solve the following equations:(a) 2(x + 4) = 12(b) 3(n – 5) = 21(c) 3(n – 5) = – 21(d) – 4(2 + x) = 8(e) 4(2 – x) = 8

(a) We have:

2(x + 4) = 12

Dividing both sides by 2,  we have : Transposing 4 to the RHS, we get  : Thus (b)  We have:

3(n – 5) = 21

Dividing both sides by 3,  we have : Transposing - 5 to the RHS, we get  : Thus (c)  We have   :

3(n – 5) = – 21

Dividing both sides by 3,  we have : Transposing - 5 to the RHS, we get  : Thus (d) We have   :

– 4(2 + x) = 8

Dividing both sides by - 4,  we have : Transposing 2 to the RHS, we get  : Thus (e)  We have   :

4(2 - x) = 8

Dividing both sides by  4,  we have : Transposing x to the RHS and 2 to the LHS , we get  : Thus ## Related Chapters

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