2.  Solve the following equations:

(a) 2(x + 4) = 12

(b) 3(n – 5) = 21

(c) 3(n – 5) = – 21

(d) – 4(2 + x) = 8

(e) 4(2 – x) = 8

Answers (1)

(a) We have:       

2(x + 4) = 12

Dividing both sides by 2,  we have :

 x\ +\ 4\ =\ 6

Transposing 4 to the RHS, we get  :     

 x\ =\ 6\ -\ 4\ =\ 2

Thus  x\ =\ 2

 

(b)  We have:     

 3(n – 5) = 21

Dividing both sides by 3,  we have :

  n\ -\ 5\ =\ 7

Transposing - 5 to the RHS, we get  :     

 n\ =\ 7\ +\ 5\ =\ 12

Thus  n\ =\ 12

 

(c)  We have   :       

3(n – 5) = – 21

 Dividing both sides by 3,  we have :

  n\ -\ 5\ =\ -\ 7

Transposing - 5 to the RHS, we get  :     

 n\ =\ -\ 7\ +\ 5\ =\ -\ 2

Thus  n\ =\ -\ 2

 

(d) We have   :       

 – 4(2 + x) = 8

 Dividing both sides by - 4,  we have :

    x\ +\ 2\ =\ -\ 2

Transposing 2 to the RHS, we get  :     

 x\ =\ -\ 2\ -\ 2\ =\ -\ 4

Thus  x\ =\ -\ 4

 

(e)  We have   :        

 4(2 - x) = 8

  Dividing both sides by  4,  we have :

   2\ -\ x\ =\ 2

Transposing x to the RHS and 2 to the LHS , we get  :       

x\ =\ 2\ -\ 2\ =\ 0

Thus  x\ =\ 0

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