Q3 Solve the following equations:

(a) 4 = 5(p – 2)

(b) – 4 = 5(p – 2)

(c) 16 = 4 + 3(t + 2)

(d) 4 + 5(p – 1) =34

(e) 0 = 16 + 4(m – 6)

Answers (1)

(a)                 4 = 5(p – 2)

Dividing both sides by 5, we get :

                                   p\ -\ 2\ =\ \frac{4}{5}

or                                            p\ =\ \frac{4}{5}\ +\ 2\ =\ \frac{14}{5}

 

(b)           – 4 = 5(p – 2)

Dividing both sides by 5, we get :

                                    p\ -\ 2\ =\ \frac{-4}{5}

or                                            p\ =\ \frac{-4}{5}\ +\ 2\ =\ \frac{6}{5}

 

(c)          16 = 4 + 3(t + 2)

Transposing 4 to the LHS and then dividing both sides by 3, we get :

                                  16\ -\ 4\ =\ 3(t\ +\ 2)

or                                  t\ +\ 2\ =\ 4

or                                             t\ =\ 2

 

(d)                4 + 5(p – 1) =34

Transposing 4 to the RHS and then dividing both sides by 5, we get :

                                   5(p\ -\ 1)\ =\ 30

or                                     p\ -\ 1\ =\ 6

or                                                 p\ =\ 7

 

(e)            0 = 16 + 4(m – 6)

Transposing 16 to the LHS, we get : 

                               -\ 16\ =\ 4(m\ -\ 6)

or                         m\ -\ 6\ =\ -4

or                                  m\ =\ 2         

Preparation Products

Knockout NEET May 2021 (One Month)

An exhaustive E-learning program for the complete preparation of NEET..

₹ 14000/- ₹ 6999/-
Buy Now
Foundation 2021 Class 10th Maths

Master Maths with "Foundation course for class 10th" -AI Enabled Personalized Coaching -200+ Video lectures -Chapter-wise tests.

₹ 350/- ₹ 112/-
Buy Now
Knockout JEE Main April 2021 (One Month)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 14000/- ₹ 6999/-
Buy Now
Knockout NEET May 2021

An exhaustive E-learning program for the complete preparation of NEET..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-
Buy Now
Boost your Preparation for JEE Main with our Foundation Course
 
Exams
Articles
Questions