3. Solve the following equations by trial and error method:
        (i) 5p + 2 = 17 (ii) 3m – 14 = 4

Answers (1)

(i) Put p = 1,

We have :     5(1)\ +\ 2\ =\ 7\ \neq\ 17

Put  p  = 2,

We have :      5(2)\ +\ 2\ =\ 12\ \neq\ 17

Put p = 3,

we have :      5(3)\ +\ 2\ =\ 17\ =\ 17

Thus the solution is p = 3.

 

(ii) Put m = 4,

we have :    3(4)\ -\ 14\ =\ -2\ \neq\ 4

Put m = 5,

we have :      3(5)\ -\ 14\ =\ 1\ \neq\ 4

Now, put m = 6,

we have :       3(6)\ -\ 14\ =\ 4\ =\ 4

Thus m = 6 is the solution.

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