11) Suppose that the electric field part of an electromagnetic wave in vacuum is 

E = \left \{ ( 3.1 N/C )\cos [ ( 1.8 rad /m)y + ( 5.4 \times 10 ^6 rad /s t )] \right \} \hat i
(d) What is the amplitude of the magnetic field part of the wave?

Answers (1)
S Sayak

From the given equation of the electric field, we can infer Electric field amplitude (E0) =3.1 NC-1

 Magnetic field amplitude (B_0) =\frac{E_{0}}{c}

=\frac{3.1}{3\times 10^{8}}

=1.03\times10-7 T

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