11) Suppose that the electric field part of an electromagnetic wave in vacuum is 

E = \left \{ ( 3.1 N/C )\cos [ ( 1.8 rad /m)y + ( 5.4 \times 10 ^6 rad /s t )] \right \} \hat i

(c) What is the frequency n?

Answers (1)

From the given equation of the electric field we can infer angular frequency(\omega) = 5.4\times10rad s-1

Frequency(\nu) = \frac{\omega }{2\pi }

=\frac{5.4\times10^{8}}{2\pi }

=8.6\times10Hz

=86 MHz

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