Q

# Suppose that the electric field part of an electromagnetic wave in vacuum is E is equal to {(3.1 N/C) cos [(1.8 rad/m) y + (5.4 × 106 rad/s)t]}ˆi . (c) What is the frequency n ?

11) Suppose that the electric field part of an electromagnetic wave in vacuum is

$E = \left \{ ( 3.1 N/C )\cos [ ( 1.8 rad /m)y + ( 5.4 \times 10 ^6 rad /s t )] \right \} \hat i$

(c) What is the frequency n?

Views

From the given equation of the electric field we can infer angular frequency($\omega$) = 5.4$\times$10rad s-1

Frequency($\nu$) = $\frac{\omega }{2\pi }$

=$\frac{5.4\times10^{8}}{2\pi }$

=8.6$\times$10Hz

=86 MHz

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