Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Suppose that the electric field part of an electromagnetic wave in vacuum is E is equal to {(3.1 N/C) cos [(1.8 rad/m) y plus (5.4 × 106 rad/s)t]}ˆi . What is the direction of propagation?

11) Suppose that the electric field part of an electromagnetic wave in vacuum is E = \left \{ ( 3.1 N/C )\cos [ ( 1.8 rad /m)y + ( 5.4 \times 10 ^6 rad /s t )] \right \} \hat i
(a) What is the direction of propagation?

Answers (1)

best_answer

E = \left \{ ( 3.1 N/C )\cos [ ( 1.8 rad /m)y + ( 5.4 \times 10 ^6 rad /s t )] \right \} \hat i

E = \left \{ ( 3.1 N/C )\sin [ (\frac{\pi }{2}-(( 1.8 rad /m)y + ( 5.4 \times 10 ^6 rad /s t ))] \right \} \hat i

The electric field vector is in the negative x-direction and the wave propagates in the negative y-direction.

Posted by

Sayak

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE introduces CCTV policy in board exams 2025; schools fixed as centres must have facility
anam-khan

CBSE gives parents, schools till October 16 to register students in Classes 9, 11
anam-khan

CBSE Board Exam 2025: Class 9, 11 registration begins today; fee details, guidelines

Latest Question