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# Suppose the initial charge on the capacitor in Exercise 7.7 is 6 mC. What is the total energy stored in the circuit initially? What is the total energy at later time?

Q7.8  Suppose the initial charge on the capacitor in Exercise 7.7 is  $6mC$ . What is the total energy stored in the circuit initially? What is the total energy at later time?

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Given

Capacitance  $C=30\mu F=30*10^{-6}$

Inductance $L = 27mH = 27*10^{-3}H$

Charge on the capacitor  $Q=6mC=6*10^{-3}C$

Now,

The total energy stored in Capacitor :

$E=\frac{Q^2}{2C}=\frac{(6*10^{-3})^2}{2*30*10^{-6}}=\frac{6}{10}=0.6J$

Total energy later will be same because energy is being shared with capacitor and inductor and none of them loses the energy, they just store it and transfer it.

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