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# Suppose, we think of fission of a _56 ^26 Fe nucleus into two equal fragments. _28 ^13 Al. Is the fission energetically possible ? Argue by working out Q of the process. Given m (_56 ^26 Fe) is equal to 55.93494 u and m (_28^13 Al ) = 27.98191 u

Q.13.16 Suppose, we think of fission of a $_{26}^{56}\textrm{Fe}$ nucleus into two equal fragments, $_{13}^{28}\textrm{Al}$ . Is the fission energetically possible? Argue by working out Q of the process. Given $m ( _{26}^{56}\textrm{Fe} ) = 55.93494\; u$ and $m ( _{13}^{28}\textrm{Al} ) = 27.98191\; u$

Views

The reaction will be $_{26}^{56}\textrm{Fe}\rightarrow _{13}^{28}\textrm{Al}+_{13}^{28}\textrm{Al}$

The mass defect of the reaction will be

$\\\Delta m=m(_{26}^{56}\textrm{Fe})-2m( _{13}^{28}\textrm{Al})\\ \Delta m=55.93494-2\times 27.98191\\ \Delta m=-0.02888u$

Since the mass defect is negative the Q value will also negative and therefore the fission is not energetically possible.

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