4.9     The activation energy for the reaction   is  at .  Calculate the fraction of molecules of reactants having energy equal to or greater than activation energy?

We have

Activation energy = 209.5KJ/mol

temperature= 581K

R = 8.314J/mol/K

Now,  the fraction of molecules of reactants having energy equal to or greater than activation energy is given as

taking log both sides we get

= 18.832

x = antilog(18.832)

= 1.471

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