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The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased to three times how will it affect the rate of formation of Y ?

4.4     The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased to three times how will it affect the rate of formation of Y ?

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M manish

The order of a reaction means the sum of the power of concentration of the reactant in rate law expression.

So rate law expression for the second-order reaction is R=k[x]^{2} here R = rate

if the concentration is increased to 3 times means x^{'}_{new}=3x

new rate law expression = R^{'}=k[3x]^{2} = 9k[x]^{2}=  9R

the rate of formation of Y becomes 9 times faster than before

                                        

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