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# The diagonals of a rhombus measure 16 cm and 30 cm. Find its perimeter.

8. The diagonals of a rhombus measure 16 cm and 30 cm. Find its perimeter.

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As we know that the diagonals of the rhombus are perpendicular to each other and intersect at a point which is mid of both the diagonal.

So. By Pythagoras Theorem we can say that

$(Hypotenus)^2=(Base)^2+(Perpendicular)^2$

$(Side)^2=\left(\frac{16}{2}\right)^2+\left ( \frac{30}{2} \right )^2$

$(Side)^2= 8 ^2 + 15 ^2$

$(Side)^2= 64 + 225$

$(Side)^2= 289$

$Side= 17\:cm$

Hence Side of the rhombus is 17 cm.

So,

The Perimeter of the rhombus = 4 x 17 cm

= 68 cm.

Hence, the perimeter of the rhombus is 68 cm.

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