8. The diagonals of a rhombus measure 16 cm and 30 cm. Find its perimeter.
 

Answers (1)

As we know that the diagonals of the rhombus are perpendicular to each other and intersect at a point which is mid of both the diagonal.

So. By Pythagoras Theorem we can say that

(Hypotenus)^2=(Base)^2+(Perpendicular)^2

(Side)^2=\left(\frac{16}{2}\right)^2+\left ( \frac{30}{2} \right )^2

(Side)^2= 8 ^2 + 15 ^2

(Side)^2= 64 + 225

(Side)^2= 289

Side= 17\:cm

Hence Side of the rhombus is 17 cm.

So,

The Perimeter of the rhombus = 4 x 17 cm

                                                 = 68 cm.

Hence, the perimeter of the rhombus is 68 cm.

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