Q : 3    The diameter of a metallic ball is \small 4.2\hspace{1mm}cm. What is the mass of the ball, if the density of the metal is \small 8.9\hspace{1mm}g per \small cm^3?
 

Answers (1)

Given,

The radius of the metallic sphere = r = \frac{4.2}{2}\ cm = 2.1\ cm

We know, Volume of a sphere = \frac{4}{3}\pi r^3

\therefore The required volume of the sphere = \frac{4}{3}\times\frac{22}{7}\times 2.1^3

\\ = 4\times22\times 0.1\times 2.1\times 2.1

\\ =38.808\ cm^3

Now, the density of the metal is \small 8.9\hspace{1mm}g per \small cm^3,which means,

Mass of \small 1\ cm^3 of the metallic sphere = \small 8.9\hspace{1mm}g

Mass of 38.808\ cm^3 of the metallic sphere = \small (8.9\times38.808)\ g

\small \approx 345.39\ g

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