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the fundamental unit which has the same power in the dimensional formula of surface tension and viscosity? explain

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it is known that,
the formula of Tension = force/Area 
So, the dimensional formula = \frac{[MLT{^-2}]}{[L^2]} = ML^{-1}T^{-2}

 the formula of viscosity = \nu = \frac{F}{A.(dv/dx)}
Therefore, the dimensional formula 
  \frac{[MLT^{-2}]}{[L^2][LT^{-2}]}=ML^{-2}T^0

Hence Mass (M) has the same power.

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manish

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