the fundamental unit which has the same power in the dimensional formula of surface tension and viscosity? explain

Answers (1)
M manish

it is known that,
the formula of Tension = force/Area 
So, the dimensional formula = \frac{[MLT{^-2}]}{[L^2]} = ML^{-1}T^{-2}

 the formula of viscosity = \nu = \frac{F}{A.(dv/dx)}
Therefore, the dimensional formula 
  \frac{[MLT^{-2}]}{[L^2][LT^{-2}]}=ML^{-2}T^0

Hence Mass (M) has the same power.

Preparation Products

JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
Buy Now
Rank Booster NEET 2021

This course will help student to be better prepared and study in the right direction for NEET..

₹ 13999/- ₹ 9999/-
Buy Now
Knockout JEE Main April 2021 (Easy Installments)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 4999/-
Buy Now
Knockout NEET May 2021

An exhaustive E-learning program for the complete preparation of NEET..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout NEET May 2022

An exhaustive E-learning program for the complete preparation of NEET..

₹ 34999/- ₹ 24999/-
Buy Now
Exams
Articles
Questions