9.10 The hexaquo manganese(II) ion contains five unpaired electrons, while the hexacyanoion contains only one unpaired electron. Explain using Crystal Field Theory.
Consider Hexaqua manganese (II) :- In this compound, the oxidation state of Mn is +2 and its electronic configuration is d5.
H2O is a weak ligand and crystal field is octahedral so the arrangement of electrons will be t23g eg2.
So the total number of unpaired electrons is 5.
Now consider hexacyanoion:- In this compound, the oxidation state of Mn is +2. It is surrounded by the strong ligands CN-, so pairing will be there.
Its arrangement will be t2g5 eg0.
Thus the number of unpaired electrons will be 1.