9.10     The hexaquo manganese(II) ion contains five unpaired electrons, while the hexacyanoion contains only one unpaired electron. Explain using Crystal Field Theory.

Answers (1)

Consider Hexaqua manganese (II) :- In this compound, the oxidation state of Mn is +2 and its electronic configuration is d5.

H2O is a weak ligand and crystal field is octahedral so the arrangement of electrons will be   t23g eg2.

So the total number of unpaired electrons is 5.

Now consider hexacyanoion:-  In this compound, the oxidation state of Mn is +2. It is surrounded by the strong ligands CN-, so pairing will be there.

Its arrangement will be   t2g5 eg0.  

Thus the number of unpaired electrons will be 1.

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