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The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1 cm^3 of wood has a mass of 0.6 g.

Q : 2    The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if \small 1\hspace{1mm}cm^3 of wood has a mass of  \small 0.6\hspace{1mm}g.
 

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Given, A hollow cylinder made of wood.

The inner diameter of the cylindrical wooden pipe = r_1 = 24\ cm
Outer diameter =  r_2 = 28\ cm

Length of the pipe = h= 35\ cm

\therefore The volume of the wooden cylinder = \pi r^2 h = \pi (r_2^2 - r_1^2)h

\\ = \frac{22}{7}\times (14^2-12^2) \times35 \\ = 22\times (14-12)(14+12) \times5 \\ = 22\times (2)(26) \times5 \\ = 5720\ cm^3

Mass of \small 1\hspace{1mm}cm^3 wood = \small 0.6\hspace{1mm}g
Mass of 5720\ cm^3 wood = 5720\times0.6\ g
\\ = 3432\ g \\ = 3.432\ kg

Therefore, the mass of the wooden hollow cylindrical pipe is 3.432\ kg

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