# 23) The normal to the curve passing (1,2) is(A) x + y = 3(B) x – y = 3(C) x + y = 1(D) x – y = 1

Given the equation of the curve We know that the slope of the tangent at a point on the given curve is given by  We know that At point (a,b) Now, the equation of normal with point (a,b) and ?
It is given that it also passes through the point (1,2)
Therefore, -(i)
It also satisfies equation -(ii)
By comparing equation (i) and (ii)   Now, equation of normal with point (2,1) and  slope = -1 ## Related Chapters

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