# 23) The normal to the curve passing (1,2) is(A) x + y = 3(B) x – y = 3(C) x + y = 1(D) x – y = 1

Given the equation of the curve

We know that the slope of the tangent at a point on the given curve is given by

We know that

At point (a,b)

Now, the equation of normal with point (a,b) and

?
It is given that it also passes through the point (1,2)
Therefore,
-(i)
It also satisfies equation                     -(ii)
By comparing equation (i) and (ii)

Now, equation of normal with point (2,1) and  slope = -1

## Related Chapters

### Preparation Products

##### Knockout NEET May 2024

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 40000/-
##### Knockout NEET May 2025

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 45000/-
##### NEET Foundation + Knockout NEET 2024

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 54999/- ₹ 42499/-
##### NEET Foundation + Knockout NEET 2024 (Easy Installment)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 3999/-