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Q. 14.8 The number of silicon atoms per m³ is $5\times 10^{28}.$ This is doped simultaneously with $5\times 10^{22}.$ atoms per $m^{3}$ of Arsenic and $5\times 10^{20}$ per $m^{3}$ atoms of Indium. Calculate the number of electrons and holes. Given that $n_{i}=1.5\times 10^{16}\; m^{-3}.$ Is the material $n-type$ or $p-type$ ?

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Given:

number of Silicon atoms per $m^{3}$ = $5\times 10^{28}.$

number of Arsenic atoms per $m^{3}$ = $5\times 10^{22}.$

number of Indium atoms per $m^{3}$ = $5\times 10^{20}$

number of thermally generated electrons $n_{i}=1.5\times 10^{16}\; m^{-3}.$

Now,

Number of electrons

$n_e =$ $5 * 10 ^{22}-1.5*10^{16}$ = $4.99*10^{22}(approx)$

number of holes is $n_h$

in thermal equilibrium

$n_h*n_e=n_i^2$

$n_h=n_i^2/n_e$

$n_h= (1.5*10^{16})^2/4.99*10^{22}$

$n_h= 4.51 * 10^9$

Now, since the number of electrons is higher than number of holes, it is an n-type semiconductor.

Posted by

Pankaj Sanodiya

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