# Q : 4     The paint in a certain container is sufficient to paint an area equal to $\small 9.375\hspace{1mm} m^2$.  How many bricks of dimensions $\small 22.5\hspace {1mm}cm \times 10\hspace {1mm}cm \times 7.5\hspace {1mm}cm$ can be painted out of this container?

Given, dimensions of the brick = $\small 22.5\hspace {1mm}cm \times 10\hspace {1mm}cm \times 7.5\hspace {1mm}cm$

We know, Surface area of a cuboid =$2(lb+bh+hl)$

$\therefore$ The surface area of a single brick = $2(22.5\times10+10\times7.5+7.5\times22.5)$

$= 2(225+75+166.75) = 937.5\ cm^2 = 0.09375\ m^2$

$\therefore$ Number of bricks that can be painted = $\frac{Total\ area\ the\ container\ can\ paint}{Surface\ area\ of\ a\ single\ brick}$

$= \frac{9.375}{0.09375} = 100$

Therefore, the required number of bricks that can be painted = 100

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