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The rate of a reaction quadruples when the temperature changes from 293 K to 313 K. Calculate the energy of activation of the reaction assuming that it does not change with temperature.

4.30   The rate of a reaction quadruples when the temperature changes from 293 K to 313 K. Calculate the energy of activation of the reaction assuming that it does not change with temperature.

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M manish

From the Arrhenius equation,

\log\frac{k_{2}}{k_{1}}=\frac{E_{a}}{2.303R}(\frac{T_{2}-T_{1}}{T_{1}T_{2}})...................................(i)
it is given that k_{2}=4k_{1}
T1= 293 K

T2 = 313 K
Putting all these values in equation (i) we get,

\log 4 =\frac{E_{a}}{2.303 \times 8.314}(\frac{313-293}{313 \times 293})

Activation Energy = 52.86 KJ/mol  
This is the required activation energy

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