# 8.9) The terminology of different parts of the electromagnetic spectrum is given in the text. Use the formula E = hv (for energy of a quantum of radiation: photon) and obtain the photon energy in units of eV for different parts of the electromagnetic spectrum. In what way are the different scales of photon energies that you obtain related to the sources of electromagnetic radiation?

$E=h\nu=\frac{hc}{\lambda}$

$E=h\nu=\frac{6.6\times 10^{-34}\times3\times10^8}{\lambda \times1.6\times10^{-19}}eV=\frac{12.375\times 10^{-7}}{\lambda}eV$

Now substitute the different range of wavelength in the electromagnetic spectrum to obtain the energy

 EM wave one wavelength is taken from the range Energy in eV Radio 1 m $1.2375\times10^{-6}$ Microwave 1 mm $1.2375\times10^{-3}$ Infra-red 1000 nm 1.2375 Light 500 nm 2.475 Ultraviolet 1nm 1237.5 X-rays 0.01 nm 123750 Gamma rays 0.0001 nm 12375000

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