# Q7.18 (b) A circuit containing a $80mH$ inductor and a $60\mu F$  capacitor in series is connected to a $230\: V$, $50\: Hz$  supply. The resistance of the circuit is negligible. Obtain the rms values of potential drops across each element.

Answers (1)
P Pankaj Sanodiya

As we know,

RMS potential drop across an element with impedance Z:

$V_{element}=I_{rms}Z_{element}$

SO,

RMS potential difference across inductor:

$V_{inductor}=I_{rms}*wL=8.22*2\pi *60*80*10^{-3}=206.61V$

RMS potential drop across capacitor

$V_{capacitor}=I_{rms}*\frac{1}{wC}=8.22*\frac{1}{2\pi*60*60*10^{-6}}=436.3V$

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