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2.6) Three capacitors each of capacitance 9 pF are connected in series. (b) What is the potential difference across each capacitor if the combination is connected to a 120 V supply?

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Given,

Supply Voltage V = 120 V

The potential difference across each capacitor will be one-third of the total voltage 

V_c=\frac{V}{3}=\frac{120}{3}=40V

Hence potential difference across each capacitor is 40V.

Posted by

Pankaj Sanodiya

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