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2.7) Three capacitors of capacitances 2 pF, 3 pF and 4 pF are connected in parallel. (a) What is the total capacitance of the combination?

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Given, 3 capacitors with C_1=2pF,C_2=3pFandC_3=4pF are  connected in series,

the equivalent capacitance when connected in parallel is given by 

C_{equivalant}=C_1+C_2+C_3

C_{equivalant}=2+3+4=9pF

Hence, the equivalent capacitance is 9pF. 

Posted by

Pankaj Sanodiya

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