1.(iv) and are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (see Fig.). If AD is extended to intersect BC at P, show that
(iv) AP is the perpendicular bisector of BC.
In the previous part we have proved that .
Thus by c.p.c.t. we can say that :
SInce BC is a straight line, thus :
Hence it is clear that AP is a perpendicular bisector of line BC.
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