2.21 Two charges –q and +q are located at points (0, 0, –a) and (0, 0, a), respectively.

(a) What is the electrostatic potential at the points (0, 0, z) and (x, y, 0) ?

 

Answers (1)

 

1)electric potential at point (0,0,z)

Distance from q_1

 d_1=\sqrt{0^2+0^2+(0-a-z)^2}=a+z

distance from q_2

d_2=\sqrt{0^2+0^2+(a-z)^2}=a-z

NOW,

Electric potential :

V=\frac{kq_1}{a+z}+\frac{kq_2}{a-z}=\frac{2kqa}{z^2-a^2}

2) Since the point,(x,y,0) lies in the normal to the axis of the dipole, the electric potential at this point is zero.

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