7. Two long and parallel straight wires A and B carrying currents of 8.0 A and 5.0 A in the same direction are separated by a distance of 4.0 cm. Estimate the force on a 10 cm section of wire A.

Answers (1)
S Sayak

The magnitude of magnetic field at a distance r from a long straight wire carrying current I is given by,

|B|=\frac{\mu _{0}I}{2\pi r}

In this case the magnetic field at a distance of 4.0 cm from wire B will be

|B|=\frac{4\pi \times 10^{-7}\times 5}{2\pi\times 0.04}             (I=5 A, r=4.0 cm)

\\=2.5\times10^{-5} T

The force on a straight wire of length l carrying current I in a uniform magnetic field B is given by

F=BIlsin\theta, where \theta is the angle between the direction of flow of current and the magnetic field.

The force on a 10 cm section of wire A will be

F=2.5\times10^{-5}\times8\times0.1 \times sin90^\circ       (B=2.5 T, I=8 A, l = 10 cm, \theta=90o)

F=2\times10^{-5} N

 

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